Faraday's Law of Electrolysis Calculator

Solve the ideal Faraday electrolysis relationship for deposited mass, molar mass, current, time, or electrons transferred.

Faraday’s law of electrolysis

Faraday’s law relates electrical charge to the amount of chemical transformation at an electrode. Charge equals current multiplied by time, and one mole of electron charge is represented by the Faraday constant.

The calculated mass is theoretical at 100% current efficiency with one specified electrode reaction. Side reactions, changing valence, mass-transfer limits, dissolution, impurities, and incomplete recovery reduce or alter measured yield.

How to use the Faraday electrolysis calculator

  1. Choose the unknown: Select mass, molar mass, current, time, or electron transfer number.
  2. Enter reaction data: Use the correct product molar mass and balanced half-reaction electron count.
  3. Calculate theoretical yield: Review the ideal 100%-current-efficiency result.
  4. Apply process efficiency: Use measured current efficiency and recovery separately for real electrolysis or plating.

Formula and variables

Current I for time t supplies charge It. Dividing by nF gives reacted moles, then multiplying by molar mass M gives theoretical mass.

m = MIt/(nF)
mDeposited mass
Theoretical electrode product mass (g)
MMolar mass
Molar mass of deposited or reacted species (g/mol)
ICurrent
Electric current (A)
tTime
Electrolysis duration (s)
nElectron number
Stoichiometric moles of electrons per mole of product
FFaraday constant
Molar charge constant (C/mol)

Copper deposition example

Pass 10 A for 3,600 s to reduce Cu²⁺ using M = 63.546 g/mol and n = 2.

Current and time
10 A for 3,600 s
Copper molar mass
63.546 g/mol
Electrons
2 mol e⁻/mol Cu
  1. m = 63.546 × 10 × 3,600/(2 × 96,485.33212)
  2. m ≈ 11.85 g

Result: The theoretical copper mass is approximately 11.85 g.

Actual deposited and recovered mass will differ when current efficiency is below 100% or material is lost.

Understanding your results

Distinguish theoretical and actual yield

The formula converts charge stoichiometrically under an ideal single reaction.

  • One ampere equals one coulomb per second.
  • Electron count comes from the balanced half-reaction.
  • Current efficiency accounts for charge consumed by competing processes.
  • Mass recovery can differ from electrochemical production.

Assumptions

  • Current is constant or the entered value is its correct time average.
  • The half-reaction and electron stoichiometry are correct.
  • Current efficiency and product recovery are 100%.

Limitations

  • Does not model current efficiency, side reactions, concentration polarization, overpotential, changing current, electrode area, mass transfer, dissolution, or recovery losses.
  • Does not balance electrochemical reactions.
  • The Faraday constant value follows the implemented constant and should be reported with appropriate precision.

Common mistakes

  • Entering hours instead of seconds.
  • Using charge number without balancing the actual half-reaction.
  • Treating theoretical mass as guaranteed plating yield.
  • Mixing grams and kilograms for molar mass or result.

Practical use cases

Electroplating estimates

Estimate theoretical deposited mass for a known current and duration.

Electrochemistry education

Connect charge, electron moles, reaction stoichiometry, and product mass.

Frequently asked questions

Why is actual mass lower than calculated?

Side reactions, less than 100% current efficiency, dissolution, incomplete recovery, and measurement effects can lower yield.

How do I choose n?

Use the number of electrons per mole of product in the balanced electrode half-reaction.

Can current vary with time?

Use integrated charge or a valid time-average current; a simple instantaneous value may be inaccurate.

Sources and review

Reviewed 2026-07-13.

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